Kalkulus Matematika · SMA medium
Hasil dari ∫023(x+1)(x−6) dx=....\displaystyle\int_{0}^{2}3(x+1)(x-6)\,dx=....∫023(x+1)(x−6)dx=....
A
3(x+1)(x−6)=3(x2−5x−6)3(x+1)(x-6)=3(x^2-5x-6)3(x+1)(x−6)=3(x2−5x−6). ∫02=3[x33−5x22−6x]02=3(83−10−12)=−58\int_0^2=3\left[\tfrac{x^3}{3}-\tfrac{5x^2}{2}-6x\right]_0^2=3\left(\tfrac83-10-12\right)=-58∫02=3[3x3−25x2−6x]02=3(38−10−12)=−58.
3(x+1)(x−6)=3(x2−5x−6)=3x2−15x−183(x+1)(x-6)=3(x^2-5x-6)=3x^2-15x-183(x+1)(x−6)=3(x2−5x−6)=3x2−15x−18.
∫02(3x2−15x−18) dx=[x3−15x22−18x]02=8−30−36=−58\int_0^2(3x^2-15x-18)\,dx=\left[x^3-\tfrac{15x^2}{2}-18x\right]_0^2=8-30-36=-58∫02(3x2−15x−18)dx=[x3−215x2−18x]02=8−30−36=−58.
Jawabannya A.
⚡ Latihan Matematika SMA