Skorr

Integral substitusi bentuk akar

Kalkulus Matematika · SMA medium

Hasil 3x22x3+4dx=\displaystyle\int \dfrac{3x^2}{\sqrt{2x^3+4}}\,dx = \ldots

  1. A
    42x3+4+C4\sqrt{2x^3+4} + C
  2. B
    22x3+4+C2\sqrt{2x^3+4} + C
  3. C
    2x3+4+C\sqrt{2x^3+4} + C
  4. D
    122x3+4+C\tfrac12\sqrt{2x^3+4} + C
  5. E
    142x3+4+C\tfrac14\sqrt{2x^3+4} + C

Kunci jawaban

C

Penjelasan singkat

Misal u=2x3+4u=2x^3+4, du=6x2dxdu=6x^2dx. u1/2du2=u=2x3+4+C\int u^{-1/2}\tfrac{du}{2}=\sqrt u=\sqrt{2x^3+4}+C.

(Jawaban dihitung & diverifikasi dengan Python/SymPy.)

Substitusi u=2x3+4du=6x2dx3x2dx=12duu=2x^3+4 \Rightarrow du=6x^2\,dx \Rightarrow 3x^2\,dx=\tfrac12du.

3x22x3+4dx=1u12du=122u=2x3+4+C\int \dfrac{3x^2}{\sqrt{2x^3+4}}\,dx=\int \dfrac{1}{\sqrt u}\cdot\tfrac12\,du=\tfrac12\cdot2\sqrt u=\sqrt{2x^3+4}+C

C.

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